In the gre math review which is mentioned in the 1 month plan(getting started), I am unable to understand how this solution. Can someone provide a detailed explanation?
(The question is in gre math review arithmetic)
When dividing -32 by 3 , the goal is to find the quotient (how many times 3 fits into -32 ) and the remainder (what’s left over). Here’s how it works:
Step 1: Find the Greatest Multiple of 3 Less than -32
First, identify the largest multiple of 3 that is smaller than -32 . The multiples of 3 going into negative values are -3, -6…-30, -33, -36 .
In this sequence, the greatest multiple less than -32 is -33.
Step 2: Calculate the Quotient
Now, determine how many times 3 goes into -33 . That would be:
-33 \div 3 = -11
Step 3: Determine the Remainder
To find the remainder, multiply the quotient (-11) by 3 and then subtract this value from -32 :
-32 - (-11 times 3) = -32 - (-33) = -32 + 33 = 1
Conclusion
The final answer is that -32 divided by 3 is -11 with a remainder of 1 . Therefore, we can express as:
-32 = (-11)3 + 1
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Thank you for the explanation . That helped me understand, however i got another question. Suppose the numbers are really big like a 5 digit number divided by a 2 digit number. At that time we will be using simple long division. In that case we will be getting the value less than the dividend. how to solve those. get the quotient .add 1 to it
I’m not sure I understand what you’re asking.
But with regards to your answer, it’s spot on
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i had a doubt and wanted to know if my solution was correct. thanks for clearing that up
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