In this question if I consider B=10 then the answer is A+C>B, but if I consider B=1 then the answer is A+C=B and that’s why I think the answer should be option D. But it says the answer is option A.
Please help.
Can you show what you get for quantity A when you consider these different values of B? For this question though, you just want to use the definition of an average.
\frac{A + C}{2} = B \implies \boxed{A + C = 2B}
Thus, Quantity A > Quantity B owing to the fact that B > 0.
I have solved it again, and I was doing a silly mistake, my bad. I got it now.