GRE Quant Problem Solving - Medium Category

A fan has forty equally-spaced blades, marked from 1 to 40, respectively, in a clockwise direction. Which blade would be directly opposite blade number 3, if such a blade exists?

Can someone please share the solution for the above sum?

Would really appreciate it, thank you!

Circle has 360° so that is cut into 40 equal parts hence each is 9°
So 1st would be at 9°
2nd = 18°
3rd=27°
So opposite means you have to go beyond half of the circle that is the number opposite to 3 will be present after half of the circle hence numbers 1-20 are present at the first half and
1 has a opposite side of 21
2= 22
3= 23
You can do this by angle aswell
180°+27°= 207°

And since each sector is 9°
207th degree would be 207/9=23
So answer is 23

Got it, thank you!

I can give you a shortcut for it: Think of the round watch with calibrated numbers from 1 to 12; if you subtract the number directly opposite to any other number on the watch (e.g. 1 is opposite to 7 or, 2 is opposite to 8), you get 6 (7-1 or 8-2). And 6 is basically one half of the max. number 12.

Similarly, for the given problem, if you subtract opposite numbers, you would get 40/2 = 20. So, for 3rd blade, it would be 23. (23-3=20)

Makes sense, got it. Thank you!