How am I supposed to solve this?

Split 270 into factors where one of those factors contains a common cube (the GRE will select a single digit number so if you do not know them you can multiply real quick in the calculator to determine).

In this case \sqrt[3]{27*10}

\sqrt[3]{27} is 3 and 3\sqrt[3]{10}-\sqrt[3]{10}=2\sqrt[3]{10}

Now do the same with the other one.

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