How am I supposed to solve this?
Split 270 into factors where one of those factors contains a common cube (the GRE will select a single digit number so if you do not know them you can multiply real quick in the calculator to determine).
In this case \sqrt[3]{27*10}
\sqrt[3]{27} is 3 and 3\sqrt[3]{10}-\sqrt[3]{10}=2\sqrt[3]{10}
Now do the same with the other one.
1 Like