GRE Quant Solution

Explanation please
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Hint: try x^2 + 2x + 1 and x^2 + 2x + 4.

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A? is it a?

its D

consider f(x) = x^{2} - 3

number of solutions for f(x) is 2

f(x)+ 3 = x^{2}

Number of solutions for f(x)+3 is 1

In this case number of solutions of f(x) are greater than number of solutions of f(x)+3

Now consider f(x) = x^{2} -6

number of solutions for f(x) is 2

f(x) + 3 = x^{2} -3

number of solutions for f(x)+3 is 2

In this case number of solutions of f(x) is equal to that of f(x) + 3. So the answer must be D