Is the answer one?

Is the answer B) One? My solution is -

For &abc& to be prime, the possibilities are -

- a and b are 0 and c=1, so &abc& becomes (2^0)
*(3^0)*(5^1), so that &abc& = 5 - a and c are 0 and b=1, so that &abc& = 3
- b and c are 0 and a=1, so that &abc& = 2

However, since abc has to be a three-digit number a cannot be 0, leaving us with only the 3rd possibility.