The question is from the OG book practice exam

Eqn of line : y = mx+b

let y intercept be (0,b)

then x intercept (y= 0)

0 = mx+b

\frac{-b}{m}=x -->Eqn1

x intercept = 2 (y) intercept (A)

\frac{-b}{m} = 2b

\frac{-1}{2}=m, where m is the slope

I guess all of them are individually sufficient to find the slope as negative first condition was explained by @HoldMyBeer

B) x intercept= -b/m and y intercept is b so product is

-b^2/m for this quantity to be positive u need m to be negative

C) slope is (b-s)/(a-r) as we know from the given condition in option either one has to be negative hence slope is negative in this case aswell