This is a very tricky question.

So take

A: 3^8 - 3^7 and B: 3^7.

A: 3^8 and B: 3^7 + 3^7

A: 3 x (3^7) and B: 2 x (3^7)

You can cancel out the 3^7 from both sides. This leaves you

A: 3 and B: 2

A: 3 > B: 2

So A.

Note: 3^7 means 3 raised to the power of 7. 3^8 means 3 raised to the power 8.

Quantity A if simplified = 3^7( 3 - 1 )

Quantity B will remain 3^7

Lets divide 3^7 from both sides

Quantity A = 2 while Quantity B = 1

Hence, A > B .

You can try with something smaller to if you’d like instead of 3^8 take 3^3 and then calculate it

ex: 3^3 - 3^2 vs 3^2

27-9 = 18 while Quantity B = 9

Hence A > B