How many diagonals can be drawn inside a regular 12 12-sided polygon?

Can someone please explain this in more detail?


Here is where I saw the question and didn’t understand the explanation

You should apply the “Create a Smaller Example” strategy here with a square or pentagon to figure out what’s going on:

For a square we can see that there:

  • 1 diagonal per corner
  • 4 corners

So we should have 1 * 4 = 4 diagonals.

However, a diagonal is shared between 2 corners, so we need to divide this by 2. So, a square has 2 diagonals in total.

We essentially need to do (# corners * diagonals per corner) / 2

To figure out the number of diagonals in a corner, try with some smaller examples:

Shape # Corners/Sides # Diagonals per corner
Square 4 1
Pentagon 5 2
Hexagon 6 3

Now, try and apply it to the 12-sided shape.

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Got it thank you!!