What this question means is you have to find the greatest common factor aka highest common factor.

Now break each number into its prime factor components.

120=2^3*3^1*5^1

210=2^1*3^1*5^1*7^1

270=2^1*3^3*5^1

Clearly the common factors for all the three numbers are 2^1 * 3^1 * 5^1…so total factors are 8 `(2*2*2)`

: **adding 1 to each of the powers**;

However, 1 is also included as a factor in those 8 factors and we have to exclude that because it says factors higher than 1…so remaining factors = 8-1 =7

I think the answer is D

You’re right bro the answer is 7

Hi thank you so much but if it’s possible could you please explain me from gcm (2

1

∗

3

1

∗

5

1

) How did we get total factors 8?

Formula for finding out total numbers of factors of a numberhttps://gmatclub.com/forum/finding-number-of-factors-of-an-integer-question-163773.html

Hey thanks a lot! I forgot the formula … Thanks a lot!