(I'm Overwhelmed) Arithmetic Progress Quiz #7 - Question 9

GRE Quant Problem Solving
1

Why is it there no consistency? Greg explains a method to solve something and when I watch solutions to quizzes the method is totally different and more confusing at times.

There are instances where Greg’s method is easier and at times the video solution is easier.
Why different methods?

Example: Quiz# 7, Question 9 solution is too confusing to understand…Even though the question is easy, i got the answer right the way i did it but the explanation is too complex!
Another example: Remainders and Exponents, video explains it good but the way its solved in quiz solutions is hard to understand.

2

Which quiz “#7”? Missing context.

3

there will always be multiple ways to solve any one question lol… if you get the right answer your way, don’t worry about it! and if you can’t understand using the provided solution, try seeing if you can apply other quant strategies to get your answer

4

This is late, but I am having the exact same issue with the same test. Working through the “I’m Overwhelmed” study plan (3 months) Module 2. Just took Quiz 7 and one of the only answers I couldn’t understand was #9. I always watch the video explanations but I’ve rewatched this specific explanation three times and I still cannot follow the method. How would I even go about trying to understand for future knowledge in situations like this?

5

Post your question in the quant section of this site.

6

@Leaderboard watching the solution video I think my explanation of this question is quite confusing. What was the intended way to solve this?

Question for reference:

2025-06-28 at 16.49.32@2x
2025-06-28 at 16.49.32@2x2424×1316 81.5 KB

7

I didn’t write this one, but solving this one on-the-fly,

\frac{a}{b} = \frac{29}{8}

so possible values of a and b would be multiples of 29 and 8 respectively:

  • a = 29, b = 8 → remainder = 5
  • a = 58, b = 16 → remainder = 10
  • a = 87, b = 24 → remainder = 15
  • a = 116, b = 32 → remainder = 20

so the remainder has to be a multiple of 5 → options D and F are correct.

Another option would be to show that, for k being a positive integer,

a = 29 b + 5

and hence multiplying by k on both sides

ka = k(29b + 5)
ka = 29kb + 5k

→ remainder when ka is divided by kb is 5k.

Quant module - 2 (overwhlemedplan) doubt
8

@user4971 does the explanation above help you understand? If so we can try adding it to the quiz

9

@ganesh apologies for the late reply! yes this response was very helpful and definitely gave me a better understanding of the problem. thank you for taking the time to solve it again! I do think it would be helpful to add to the quiz.

1 Like
10

@Leaderboard could you please add this as the solution for this question?

11

It’s a video; do you want me to add it as an addendum or …?

12

Just set it as the solution for that question specifically, I think it will show up on the quiz above the video, but you can also add a note if you wish

13

Done.

1 Like
14

Hi Ganesh, understood it better. Thanks

15

Hi,

I understand my question is coming months later and I recognise that I must be missing something so please help me with this.

In this question, the remainders 10, 15 and 20 are greater than the denominator and I understand that when this is the case, one needs to further divide by the denominator to get the true remainder. Please in what instances does this rule apply because it clearly was not applied here.

Thank you!

16

What do you mean?