Latest problem solving question?

The points (0, k), (0,-k), (k, 0)(0,k),(0,−k),(k,0), and (-k, 0)(−k,0), where k=/=0, comprise the vertices of a square. What is the area of the square?

The answer key says it’s 2k2, but my calculations show it’s 4k2. Each side is length 2k so it would be (2k)2 which is 4k2

No, it’s 2k2. See the POTD (problem of the day) for July 8th.

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Thanks. I misread and did not realize the vertices