Hello! I am having trouble with these two problems. For Q23 after 115 cycles or the 460 cars there would be 3 remaining cars and you start the cycle again red (461), blue (462) and then it would land on the black car (463). I used this process on Q24 but go the wrong answer. After 14 cycles or 98 days there would be 2 remaining days and you start the cycle again so Tuesday (99), and then it would land on Wednesday (the last day to get to 100). But that was wrong and it was Thursday. So how did this process work for Q23 but not for Q24? If anyone could help that would be great!

So you have your fundamentals clear, you just did a little mistake. See, Jason deposited money on a Tuesday, which means that after the 14 cycles or 98 days, it would be a Tuesday. Now add the remaining 2 days, which is Thursday. Got it?

Hello, still a little confused :(. So then now with your process and looking at Q23 if we start with red and then the 115 cycles or 460 cars it would start back again at red and then add the remaining 3 cars which would gray instead of black being the answer.

Q23 : RED BLUE BLACK GRAY ( The first car is Red, i.e. Car#1 is red. )

So if you go 1-Red, 2-Blue, 3-Black, 4-Gray… 460 (multiple of 4)-Gray, then 461-Red, 462- Blue, 463-Black.

Another way to think is, one car has exited (red), now 462 more to go. So find 460 cars will get you back where you started (red). 2 more to go, which brings you at black.

Q24: Same concept- Start on Tuesday. 7 days later its also a tuesday. 98(multiple of 7) days later its also a tuesday. add 2 more days, so its a thursday!

Hope it helped? If not try to do the Q23 ( as 5 days later) and Q24 ( as 9 days later) and manually count the days. Maybe that helps in correctly establishing the pattern.