Hi, could anyone help me with this question? The solution provided doesn’t seem like fitting with the question

For the first part, when Harpreet buys Ticket on March 1st, he has to pay $140. If he buys the same ticket on March 2nd, he has to now buy it as $168.

Percentage increase = (168-140)/ 140 = 28/140 = 0.2. Therefore, 20%.

Similarly, when he buys the ticket on Match 16th, he has to pay $210 now. But we have to find the percentage increase relative to March 2nd price here. Hence,

Percentage increase = (210-168)/168 = 42/168 = 0.25. Therefore, 25%.

Now, we simply have to find the absolute difference between these two i.e. |25-20| = 5%.

If you are confused with the price v/s dates mentioned, for understanding you can consider then as normal airfares. As purchase dates get closer to the departure date, prices increase.

- If he buys before or on 1st March - $140
- If he buys after 1st March but on or before15th March - $168 (March 2nd fits here)
- If he buys it after 15th March but on or before 31st March - $210 (March 16th fits here)

But how did you come up with the date range? like from 2nd march to 15th march, he’ll buy at 168?

Isn’t it possible that from 1st to 14th march, ticket fares are same i.e. 140?

The table mentions “when purchased by”. Hence, March 2nd comes in the “when purchased by March 15” price, which is $168.

It implied that if the price of tickets purchased by March 1 is $140. Then after March 1 to March 15, it will be $168.

We definitely cant keep it $140 throughout because of this “when purchased by” condition. A more suitable one would be why can’t we buy it all at $210 itself since all the dates come before March 31 itself. However, its safe to say this is not the case otherwise 0% would have been one of the options (Since the price didn’t change, there was no % increase) .