Manhattan book gives an explanation that angle ABD= 180-2x
Why can we assume this is the case if we truly don’t know if line AC is straight? Why is angle ABD + angle CBD= 180?
Going further, why is line AB = line BD ???
Thanks
Manhattan book gives an explanation that angle ABD= 180-2x
Why can we assume this is the case if we truly don’t know if line AC is straight? Why is angle ABD + angle CBD= 180?
Going further, why is line AB = line BD ???
Thanks
In QC, you can assume, what looks to be a straight line to be a straight line. Thus AC is a straight line here.
u understood this right?
If yes, then in triangle ABD
Angle DAB + Angle ABD + Angle BDA=180
therefore, Angle DAB+ 180-2x + Angle BDA=180
Also, Angle DAB =x
so, x + 180-2x + Angle BDA=180
and finally, Angle BDA = 180 - 180 +2x - x
Angle BDA=x
since, Angle BDA = Angle DAB =x
line AB = BD by isosceles property of triangle