Manhattan Ratio & Geometry

1.


For this one **
I considered the Final exam marks to be 100
So then
** H Q FE

** 20% 50% 30%**

** 90% **
**Score 18/20 **

For quiz if I remove 13 then wud it be 17+15+19=53
Then calculate 53/60 and then find 88% of 50
But then I get the ans as 28

when I solve the eq
18 + 44 + x = 90

2.


Over here when you consider the height to be 3x and the base as x u get the ans as C
I assumed the hyp to be 3x then I had to redo it and it was time consuming
Is there any way to do it intuitively atleast for taking the right sides

3.


I did 8H + 12M + 4S = 36 C
36 Cups = part / total = 12/24
then cross multiply to check for 9 cupcakes

4.


I am confused on converting that line to an algebraic expression is it
No of boys leaving = no of girls entering how do I equate it to a ratio

There is no evidence that ABC is a right-angled triangle.

I don’t know what you want from Q3

Let the number of girls that joined be G. We have

\frac{8 + G}{20 - 2G} = \frac{7}{4}

Solve for G. B = 2G.

3.

I did 8H + 12M + 4S = 36 C
36 Cups = part / total = 12/24
then cross multiply to check for 9 cupcakes

I want to know if my approach for Q3 is correct

Your solution sounds convoluted.

I’d just set up a simple relation:

12 cups/36 cupcakes → x cups/9 cupcakes

x = 3

Yes I kno there is no evidence but then in the manhattan they considered it so

A key part of the question is missing in your screenshot:

My bad Thank you

U have any idea about the first one?

I know the answer, but I will refrain from giving the answer because I suspect that the question has a flaw.

I had a doubt here so when we dont consider the lowest score we just divide the 3 scores by 4 right

We divide by 3. There are only three quizzes considered in the end.

cool thanks again