I was unable to understand the problem,So according to me we want approximate sum of 1/43+1/44+1/45+…+1/48. Then how are we getting our answer by multiplying 1/43 with 6 and 1/48 with 6

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If all 6 terms were equal to 43. The sum of reciprocals is 6/43 approximately 1/7

If all 6 terms were equal to 48. The sum of reciprocals is 6/48 which equals 1/8

Since we are taking sum of reciprocals of consecutive integers between 43 and 48, the sum should be greater than 1/8 and less than 1/7.

So, choosing from the options our final answer will be closest to 1/8 than all other options.

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