Answer : A ( I understand the solution)
Doubt:
I know that when the vertex of inner square is exactly at the midpoint of the outer square , the area of the inner square is minimum, at this minimum configuration the theta = 45.
But now when we increase the theta my rotating the inner square, the area of the inner square must increase as it has already crossed its minimum area configuration.
So the area of the inner square is increasing as the theta approaches 60 degree but how can we objectively conclude the its area at theta 60 < compared to when theta 10 degree?
BTW: according to ChatGPT y is greater than x, it justified using certain trigonometric formula.