You can solve it by plugging in numbers for S and T in the equation to get the value of k, and then increase S by 50% and the substitute constant K to find the new T.

For example:

Let, S=10 and T= 2.

10 = k/2 ; so we get k= 20.

Now increasing the value of S by 50% we get S=15, and we know k= 20.

So, 15= 20/ T. We get t = 1.333333.

Which makes the decrease in value of T= 33.33%. [( 2- 1.333)/2 ]

but what if we take s=2 and t=10? Should S be greater than T?

S = k/T

=> T`1`

= k/S`1`

With a 50% increase,

S`2`

= k / (T`2`

)

1.5S = k / (T`2`

)

=> T`2`

= k / (1.5S)

T`2`

= 0.667 * k/S

# => T`2`

= 0.667 * T`1`

This is a 33.33% decrease.

No it does not matter what you take as the value of S and T, What we are concerned with is the change in value of T when S is increased by 50%. The answer will be same even when you take S=2 and T= 10.

As k=20.

New s=3.

So 3=20/T. Therefore new T= 6.6667. Decrease in percentage= 33.333% [(10-6.667)/10].

Can you please add a spolier tag while sharing PowerPrep questions

Is this a powerprep question?

Yes