You can solve it by plugging in numbers for S and T in the equation to get the value of k, and then increase S by 50% and the substitute constant K to find the new T.
For example:
Let, S=10 and T= 2.
10 = k/2 ; so we get k= 20.
Now increasing the value of S by 50% we get S=15, and we know k= 20.
So, 15= 20/ T. We get t = 1.333333.
Which makes the decrease in value of T= 33.33%. [( 2- 1.333)/2 ]
but what if we take s=2 and t=10? Should S be greater than T?
S = k/T
=> T1 = k/S1
With a 50% increase,
S2 = k / (T2)
1.5S = k / (T2)
=> T2 = k / (1.5S)
T2 = 0.667 * k/S
=> T2 = 0.667 * T1
This is a 33.33% decrease.
No it does not matter what you take as the value of S and T, What we are concerned with is the change in value of T when S is increased by 50%. The answer will be same even when you take S=2 and T= 10.
As k=20.
New s=3.
So 3=20/T. Therefore new T= 6.6667. Decrease in percentage= 33.333% [(10-6.667)/10].
Can you please add a spolier tag while sharing PowerPrep questions
Is this a powerprep question?
Yes