So one equation is y=x^2 and another is x=y^2
in case one for x (+1, -1) the value of Y remains same for second case y(+1,-1) the value of X remains same and the exponents are even as well so marked both of them even not able to understand why the second function that is x=y^2 can’t be even
For an even relation, you need both (x,y) and (-x, y) to exist.
In other words, you need the graph to be symmetric about the y-axis. Is a sideways parabola symmetric about the y-axis?
No, that’s not the case. It’s symmterical about x axis. Got it
Thanks
