Prob Q from Arithmetic and Algebra Session 2

Hello guys,

I understand why 36 = n, and thus why Greg chose 12 and 36 as the correct answers, but I still do not understand why 72 cannot be n as well. If 72 = n, then n^2 = 5184 which it is a multiple of both 24 and 108.
So, Is 72 not a correct answers because then 24 (a divisor of 72) is not of divisor of 36 (which is also n)? Hope that makes sense.

Yes!

Yes 72 is a valid multiple!

In fact, this is the set S = {36, 72, 108, 144, 180, 216,…}
S is a multiple of an infinite set, BUT what numbers would guarantee the divisibility of every numbers in S? That has to be a 36, right?

So, Basically, all the factors of 36 would be the correct answers: {1, 2, 3, 6, 9, 12, 18, 36}

For example,
If you would divide the first five numbers of the set S by 9
You would get: {4, 8, 12, 16, 20}

See, the factors of 36 guarantee that divisibility, but 24 and 72 don’t.

Hope this helps!

Now it makes sense. Thank you!!!

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