why is 6! divided by 3! two times. I get that there are three 5s, for that we get one 3!, but where does the other 3! come from? The other three values can be anything other than 5.
its the combinations formula lol
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For more relevant information, you can seek out “binomial distribution”. You see the “combination bit” in the general formula so yeah.
Otherwise, you can just see it as:
Let getting a 5 be represented as t and getting another number besides 5 be represented as as k, so an arrangement could be:
tttkkk → The number of arrangements of this is simply \frac{6!}{3! \cdot 3!}
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Thanks!