Probability of choosing 3 sides at random


Can anybody help me with this problem, more of a quicker method?

Nah
I think you will just have to list out all combinations and see if they are a triangle
3, 5, 7 - triangle
3, 5, 9 - not triangle
3, 5, 11 - not triangle
3, 7, 9 - triangle
3, 7, 11 - not triangle
3, 9, 11 - triangle
5, 7, 9 - triangle
5, 7, 11 - triangle
5, 9, 11 - triangle
7, 9, 11 - triangle

P = 7/10 = 0.7

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