Probability question : BOOTHS

I dont understand the what to do here?

I did it this way:

Possible ways of sitting
1 BOOTH : AAAA BBBB CCCC DDDD
2 BOOTHS : 4C2 * 4! /2! 2!
3 BOOTHS : 4C3 * 4! /2!
4 BOOTHS : ABCD => 4!

4! / TOTAL 24/72

Focus on the 4 booths part. You have 4! different rearrangements possible - and in how many ways can he sit when he arrives four times independently?