Please help me solve comparison question:
A =98^98+99^99
B=100^100
for B = 100^100 = 10^200
for A consider 98 and 99 = 100 (approx.)
then, A = 100^98 + 100^99 = 10^196 (100+1) = 10^198 (approx.)
So, B > A
Please help me solve comparison question:
A =98^98+99^99
B=100^100
for B = 100^100 = 10^200
for A consider 98 and 99 = 100 (approx.)
then, A = 100^98 + 100^99 = 10^196 (100+1) = 10^198 (approx.)
So, B > A