Quant Problem | Geometry

In this question, I believe, CR can be greater than RQ if we use the angles side property, which makes the answer D.

You’ll need to explain further.

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I will probably solved it this way (Don’t know the solution so correct me if I am wrong!)
As In triangle CPQ rt. angled at P → angle C = 60 ; Angle P = 90 and Angle Q = 30 (180 - 90 -60 = 30)

Now, in Triangle CPR : CP = CR (radii of the circle) and Angle C = 60 .

We know that angle opposite to equal sides are also equal thus, let the Angle P be x hence, Angle R will also become x. Now, x +x+60 = 180 or x=60 → Triangle CPR is equilateral!

Now , in Triangle RPQ : Angle Q = 60 , Angle P = 30 (90 - 60= 30) and Angle R = 90 (180 - 30 - 60 = Angle R).

Now, RQ is opposite to angle 30 while CR is opposite to angle 60 and we know that side opposite to the larger (greater) angle is longer.

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But that’s two different triangles…

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Got it. Even I was considering both the triangles to compare.