In this question, I believe, CR can be greater than RQ if we use the angles side property, which makes the answer D.

Youâ€™ll need to explain further.

I will probably solved it this way (Donâ€™t know the solution so correct me if I am wrong!)

As In triangle CPQ rt. angled at P â†’ angle C = 60 ; Angle P = 90 and Angle Q = 30 (180 - 90 -60 = 30)

Now, in Triangle CPR : CP = CR (radii of the circle) and Angle C = 60 .

We know that angle opposite to equal sides are also equal thus, let the Angle P be `x`

hence, Angle R will also become `x`

. Now, x +x+60 = 180 or x=60 â†’ Triangle CPR is equilateral!

Now , in Triangle RPQ : Angle Q = 60 , Angle P = 30 (90 - 60= 30) and Angle R = 90 (180 - 30 - 60 = Angle R).

Now, RQ is opposite to angle 30 while CR is opposite to angle 60 and we know that **side opposite** to the **larger** (**greater**) **angle** is longer.

But thatâ€™s two different trianglesâ€¦

Got it. Even I was considering both the triangles to compare.