if a>b>c>0 and abc=231. Find a+b+c? -one of the options is cannot be determined and the others are some two digit integer.
source?
21 is the answer… As abc=231…which is equal to 3.7.11
Three prime numbers…as a>b>c so 11>7>3.
Though this is there just got confirmation of the values. Doesn’t matter in which way the numbers are arranged.
a+b+c =11+7+3 =21
Its from counselling class test called greedge…
I do think I remember this option was there. but how did you arrive at it given it is a time-based and juggling the numbers will totally be a waste of time?
Lol by practice …I literally solved this without a pen or paper and in 10 seconds I swear …My NIT degree is of some worth I suppose XD…but it’s mostly practice! Lol, you’ll get there…I have my GRE tomorrow. Wish me luck!
All the best !!!
What are the materials you have used for practice? The concepts are clear for me but need practice…
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Thanks…Arrived at it because of a+b+c. Now see a+b+c doesn’t depend on what you choose the values…a>b>c is there to confuse you…if they would’ve asked you the values of a, b and c separately then the inequality would have made sense…
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Manhattan 5lb…ETS and Greg’s problems bunch of stuffs here and there…whenever I got bored of English I studied quant…Also strong base since childhood…there cannot be any replacement for that…my mum’s a mathematician and dad’s an IITian so probably runs in the family! 
You can try one thing…Try making your own problems…that really heightens the critical thinking skills…how can I modify the problem so that people are not able to solve in the first place…try doing mental maths and practice everyday!
Haha makes sense now… but thanks for clarifying… Also for verbal - is there anything more you had done to help you out?
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Math was actually my strongest point but years of working in the IT industry drove me away from the subject 
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Refer above…well Greg’s So YOu Think You Know Words are 24 carat gold…trust me…just mug them up like there’s no tomorrow and apply his strategies…I am not a fast reader and 2 months cannot make me a fast reader…My strategy is solving around 17 problems with 98% accuracy and guessing the last 3!
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Happens to the best of us :’(
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Really smart choice regarding pace and dash at the end for RC so you can bag some correct answers
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Try coming up with something crazy like an equivalent of soduku by Maki Kaji who recently passed away!..Sudoku blows my mind!
Totally…another thing would be if you are working it’s very difficult to focus on GRE because for me I graduated 5 years ago…I had forgotten most of it…while solving I used to visit a lot of differentiation, physics and integral concepts…even coordinate…ellipse and all…It brought back so many memories of high school…I loved science then and now…if you do these time to time it’s a good refresher I believe…also some trig here and there…though not disparaging anyone…This is not required…It’s what kept me going other than Greg sagacious yet cheeky aphorisms…Also I read few pages of a story book every night…I can’t get myself to the level of reading Carl Sagan though I admire him a lot…but unintelligible vocab throws me off…so I stuck with fiction
Currently reading Arundhati Roy’s The God of Small Things!
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Really appreciate it @koala for your insightful thoughts. I’m sure this might take me back to “the” days. Will give it a go.
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I think a quick and efficient way of figuring it out without just doing random numbers is dividing 231 by a few numbers. I knew it couldn’t be divided by 2, 4, 5, or 6 since it ends with a one so I tried 3 and got 77 which was fairly easy to see could be divided into 7 and 11 and it worked. So maybe just try to divide it by a certain number and go from there!
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That could also work plus you got calculator to the calculations quickly. A little thing to add is if you memorize the divisibility rules then you can immediately tell if a number is divisible by a number in the range 1-10 . For eg: Divisibility by 3 is if the sum is divisible by 3 then the number is divisible by 3, thus 2+3+1=6 & we know 6 is divisible by 3 thus 231 is divisible by 3.
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