The advertised size of a television is the length of the diagonal of the rectangular viewing screen. For a television advertised as 42-inch, if the ratio of the lengths of the sides of the viewing screen is 16 to 9, approximately what is the area, in square inches, of the viewing screen?
a) 144 b) 328 c) 406 d) 754 e) 933
(16x)^2+(9x)^2=42^2
\frac{1764}{337}=x^2
5.23=x^2
2.28=x
Putting value of x and finding the area of rectangle:
16(2.28)\times9(2.28)=748 \sim \text{Option D}(754)
Thank u so much.