Need solution to the below mentioned problem:

TIA

Need solution to the below mentioned problem:

TIA

@HoldMyBeer @Leaderboard , need your expertise

The area of the graph is much bigger from 20-80 than 10-70 so B is greater

(do not ping users like that)

What’s the common area between [10, 70] and [20, 80]? It’s [20, 70], Then you are left with comparing the areas between [10, 20] and [70, 80]. Recall that in a normal distribution, most of the values are bunched towards the mean. What does this tell you in this case?

How are you certain that number of students scoring [70,80] are found close to the mean(i.e within a std deviation above mean).

For eg: You might find students scoring (50-60] within a std deviation above mean(i.e 34% area utilization) and number of students scoring [60,80] at mean+2*sd(under 14% area) and can still end up ambiguous in discerning the area swept by the intervals respectively right ? or am I missing something?

It would be of great help if u can point me to a conceptual video addressing this problem.

They are only saying close to the mean, not within the first standard deviation of the mean

75 - 50 = 25

50 - 15 = 35

Thus 70 - 80 is closer to the mean

If you look at the standard deviation curve, all values that are closer to the mean will have a higher frequency, irrespective of what is the standard deviation