Does anyone know why in this equation 0 is considered a valid value of x, if the denominator is x^2-4? I concluded that the values of x that do not work are 2, -2 and 0. Thanks!
Hello!
I am missing a bit of crucial context here, like the numerator, but upon first look, it seems that 0 is, in fact, a valid x value.
Reason being that the denominator is only 0 at x = -2 and x = 2, which would make the world explode. Or maybe not. Let me rephrase. It would make the GRE explode, and that’s our focus here, so don’t detonate the denominator.
I think the confusion is that 0 by itself is not an acceptable denominator. 0 when plugged into the equation is acceptable here because when evaluated, it just becomes -4.
Let me know if this helps!