https://prepswift.gregmat.com/quizzes/quiz/prepswift-finding-the-minimum-value (Question 2)
In this question, I multiplied both sides by -ve sign, to ensure that the RHS is in a more familiar quadratic equation state, with x^2 being positive.
I then used completing the square method and the final equation came out to be y= - (x+0.5)^2 + 1.25.
Looking at this equation, I thought the answer is D. (x+0.5)^2 will always be non-negative. But due to a negative sign outside the brackets, it will always be negative.
Which means that if x=0, then y = 1. But if x>1, then y < 1.
Can you please explain what I did wrong?
