The ratio of 16 to g is equal to the ratio of g to 49.
Quantity A: g
Quantity B: 28
This is a question from 5lbs. Book of GRE practice
\frac{16}{g} = \frac{g}{49} or g^2 = 16 \times 49
on solving for g we get g = \pm \sqrt{4^2 \times 7^2} \text{ or } g = \pm28
Would the answer be D because g could be positive 28 or negative 28?
yeah, thats the answer. But in the class, Greg said not to consider negetive when the root is removed.
I think you’re slightly mis-interpretating what he must have actually told !
Read this article to clear your doubt :https://magoosh.com/gre/positive-and-negative-square-roots-on-the-gre/
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Thank you so much. This helped!! 