The ratio of 16 to g is equal to the ratio of g to 49.

Quantity A: g

Quantity B: 28

This is a question from 5lbs. Book of GRE practice

\frac{16}{g} = \frac{g}{49} or g^2 = 16 \times 49

on solving for g we get g = \pm \sqrt{4^2 \times 7^2} \text{ or } g = \pm28

Would the answer be D because g could be positive 28 or negative 28?

yeah, thats the answer. But in the class, Greg said not to consider negetive when the root is removed.

I think you’re slightly mis-interpretating what he must have actually told !

Read this article to clear your doubt :https://magoosh.com/gre/positive-and-negative-square-roots-on-the-gre/

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Thank you so much. This helped!!