Solve x(x-2)/((x-3)(x-4)^2) = 0

From Arithmetic and Algebra Session 10, time 1:00:00

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for 2nd part.

We have x=0,2

For x=0 the quantities A and B are undefined, hence we can’t compare them.

So why the answer is not D?

Because x = 0 is undefined and hence does not count (ideally they should mention this in the question though).

The answer is not D because if you simplify quantity B, you get quantity A + \frac{1}{x^2}, which is always positive. Hence B > A.

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