Solving Mixture problem using Distance

Is there any easier way to solve this using distance or ratio and not using the weighted average formula?


Have you looked at the Mixture Trick on PrepSwift?

yeah I did, and thats what i am asking how can i implement that concept in here?

@Leaderboard can you guide me on how to use the Mixture Trick here for the above question?

It may help to view the below solution with reference to the above slide.

If we use the mixture trick,

A = 25%
B = 34%

We want 30% in the mixture

So

|required - A| = 5%
|required - B| = 4%

A/B = 4/5

Now, let’s consider the actual values:
A = 50, B = 30 + x (where x is the additional amount being added)

We have

\frac{50}{30 + x} = \frac{4}{5}

Solving for x,

250 = 4(30 + x)
130 = 4x
x = 32.5

That’s less than Quantity B, making the correct option A.

This is not a method I tend to personally use, because I think the weighted average method isn’t that bad.

1 Like

Thanks a ton @Leaderbord, already given weights spooks me.