Test 26 q no 30 very tricky sum

Can someone pls solve this sum using plug in values ?

say x=6 , y= 1 sec and z=60 sec

so original rate is 1 mile per 1 second

convert miles per sec to miles per min (multiply by 60)
In one second , distance travelled
\frac{\frac{x}{6}}{y}=\frac{x}{6y}

therefore in 1 minutes, the distance travelled will be:
\frac{x}{6y}\times60=\frac{10x}{y}

Finally in z minutes it will be :
\frac{10x}{y}\times z

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