in this question, if instead of half, the tank was filled to it’s 3/4 or 1/4 of its capacity, then how could we solve it, please?

That would be out of syllabus I think

No, I don’t see how the approach would be any different.

The answer will remain same in both the scenarios.

Can you please explain? the radius is 3, in case of 1/4 capacity, the h = 2

then how is that going to remain the same?

Really how would you solve it??

This how I solved with 1/2 volume:

πr²h = 36π

r²4 = 36

r² = 9

r = 3

When the cylinder is on its side the level of water would cover half the surface of the curved side of the cylinder, and its length = R = 3

This last piece of information is not given to us in case of 1/4 of 3/4 of water.

That is when 1/4 of the circular surface is filled we don’t know the height that water would reach.

THAT PART I asked you about how you solve it!

Thanks for explaining any ways