in this question, if instead of half, the tank was filled to it’s 3/4 or 1/4 of its capacity, then how could we solve it, please?
That would be out of syllabus I think
No, I don’t see how the approach would be any different.
The answer will remain same in both the scenarios.
Can you please explain? the radius is 3, in case of 1/4 capacity, the h = 2
then how is that going to remain the same?
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Really how would you solve it??
This how I solved with 1/2 volume:
πr²h = 36π
r²4 = 36
r² = 9
r = 3
When the cylinder is on its side the level of water would cover half the surface of the curved side of the cylinder, and its length = R = 3
This last piece of information is not given to us in case of 1/4 of 3/4 of water.
That is when 1/4 of the circular surface is filled we don’t know the height that water would reach.
THAT PART I asked you about how you solve it!
Thanks for explaining any ways