The number of integers from 1-9 that n + (n+1) + (n+2) is divisible by

The answer is 2, but n can’t be 0 because n is a positive integer. So for every n isn’t it divisible by at least 3 numbers? 123=6, 234=9…

Two steps to this question

Find which of those integers from 1-9 “n + (n+1) + (n+2)” is ALWAYS divisible by?

e.g is it always divisible by 1, 2, 3, 4? Which ones? Which integers are always a factor no matter what “n + (n+1) + (n+2)” is

Second step - How many we there?

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Oh got it, in that case, it would only be 1,3. Thank you so much!

Great, happy to help