According to the answer, the number for Quantity A is five (7, 1+6, 1+2+4, 2+5, 3+4). But since we can only sum “positive integers,” shouldn’t we exclude 7 since it is the sum of 7 and 0 (not a positive integer)?
In that case, you would also be eliminating the 7 from contention in Quantity B as well, so I believe the answer would still be C.
Why arent we accounting for the number of ways we can add the numbers up?
For Ex: In Q(B) , 1+3+3, but also 3+1+3 ,3+3+1.
Because two copies of 3 and one copy of 1 sum to 7, the order in which they are placed has little bearing on the assertion that they add to 7.