Tickbox Quiz #4 under Algebra Column 1

PrepSwift Quant Tickbox Quiz #4 (Algebra Column 1)


Basically the problem is Question 11 of 20
Basically if we solve = x2 - 2xy + y2
this can be either = (x-y)2 or (y-x)2
isn’t it? then answer to this question should be the relationship can’t be determined
Kindly help

(y - x)^2 = (-1)^2(x - y)^2 = (x - y)^2

Since squares are always positive, both are equal.
We write it as (x - y)^2 just to match the numerator, which is x - y. That way, we can simplify easily:

\frac{x - y}{(x - y)^2} = \frac{1}{x - y}

Which is exactly Quantity B.

We can do this because,
\frac{x - y}{(x - y)^2} = \frac{x-y}{(y-x)^2}

Example:
Let x = 4, y = 1

Quantity A:

\frac{4 - 1}{4^2 - 2(4)(1) + 1^2} = \frac{3}{16 - 8 + 1} = \frac{3}{9} = \frac{1}{3}

Quantity B:

\frac{1}{4 - 1} = \frac{1}{3}

You can do it the other way x = 1, y = 4. You will get the same result A=B

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