Basically the problem is Question 11 of 20
Basically if we solve = x2 - 2xy + y2
this can be either = (x-y)2 or (y-x)2
isn’t it? then answer to this question should be the relationship can’t be determined
Kindly help
Since squares are always positive, both are equal.
We write it as (x - y)^2 just to match the numerator, which is x - y. That way, we can simplify easily:
\frac{x - y}{(x - y)^2} = \frac{1}{x - y}
Which is exactly Quantity B.
We can do this because, \frac{x - y}{(x - y)^2} = \frac{x-y}{(y-x)^2}