Question 23
I would like to know the approach to solve this kind of problem. Note the answer is Quantity B.
So the best way according to me is to find the LCM of the numbers 22 and 30. This turns out to be 330. Now let’s say for the 330 distance, the car used 1 gallon for 22 miles so in total for the first half it used 330/22 which is 15 gallons. For the second journey, similarly, it used 330/30 which is 11 gallons. In total it used 15+11 = 26 gallons for 660miles.
Now look for QA: Average gas mileage in miles/ gallon is 330+330 (total trip) / total gas used ie 26 which will be equal to 25.38
QB = 26
Hence QA<QB