Why is the height x/sqrt(3) instead of just “x”, when it correspond to 30 deg? Since AB = 6, and because it corresponded to 90 degree, wouldn’t it be 2x = 6 and x = 3?
From: A Seemingly Impossible Problem exercise
Why is the height x/sqrt(3) instead of just “x”, when it correspond to 30 deg? Since AB = 6, and because it corresponded to 90 degree, wouldn’t it be 2x = 6 and x = 3?
From: A Seemingly Impossible Problem exercise
x can be whatever you want. Your numbers are relative to what you define as x.
If you define x to be \overline{AC} then \overline{BC} = x \sqrt{3}, and thus \overline{AC} = 2x.
In a similar fashion, if you define x to be \overline{BC} then \overline{AC} = \frac{x}{\sqrt{3}} and \overline{AB} = \frac{2x}{\sqrt{3}}
I responded to you here: https://www.reddit.com/r/gregmat/comments/1hw5tw9/i_am_so_confused_isnt_the_height_supposed_to_be_x/
Okay i guess you already got the same answer I gave you from leaderboard. Please don’t multipost next time cuz you’re just wasting the effort/time of others.
I don’t exactly considered your answer a waste of effort because it’s always help to see different explanation and perspective. What if I somehow didn’t understand another explanation but I understand your?
Regardless, thanks for helping out