Word problems (manhattan 5) -chap 8 minor problems type

please walk me through these problems… TIA.

1)Orange Computers is breaking up its conference attendees into groups.
Each group must have exactly one person from Division A, two people from
Division B, and three people from Division C. There are 20 people from
Division A, 30 people from Division B, and 40 people from Division C at the
conference. What is the smallest number of people who will NOT be able to
be assigned to a group?

  1. An eccentric casino owner decides that his casino should only use chips in $5
    and S7 denominations. Which of the following amounts cannot be paid out
    using these chips?

1)Each group must have 1 person from A, 2 from B and 3 from C.

since each group has most people from C, we check how many groups can be formed to completely distribute people from group C: 40/3 = 13.3333 hence 13 groups can be formed at maximum.

therefore,
A → 20 - (1 x 13) = 20 - 13 = 7 people remain
B → 30 - (2 x 13) = 30 - 26 = 4 people remain
C → 40 - (3 x 13) = 40 - 39 = 1 person remains

therefore 7 + 4 + 1 = 12 people will NOT be able to be assigned to a group.

1 Like