Working continuously 24 hours a day, a factory bottles Soda Q at a rate of 500 liters per second and Soda V at a rate of 300 liters per second. If twice as many bottles of Soda V as of Soda Q are filled at the factory each day, what is the ratio of the volume of a bottle of Soda Q to a bottle of Soda V?
(A)3/10
(B)5/6
(C)6/5
(D)8/3
(E)10/3
How to Solve this?
Given:
In 1 day -
Soda Q = 500 L
Soda V = 300 L
(Ignoring the calculation for the number of seconds in 24 hrs, since they get cancelled out later)
Assume 1 bottle of Soda Q is 10L
No. of bottles of Soda Q produced per day = No. of litres of Soda Q / Capacity of 1 bottle of Soda Q
=> (500L)/10L = 50 bottles per day of Soda Q
No. of bottles of Soda V produced per day = 2 x No. of bottles of Soda Q produced per day (Given)
=> 2 x 50 = 100 bottles per day of Soda V
100 bottles per day of Soda V = 300L of Soda V (Given that 300L of Soda V is produced)
1 bottle of Soda V = 300/100 = 3L
Therefore, ratio of 1 bottle of Soda Q : Ratio of 1 bottle of Soda V = 10 : 3
Answer: E